The total number of stereoisomers possible for 2,3-dichlorobutane are:

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Solution

The correct option is B 3

The total number of stereoisomers possible for 2,3-dichlorobutane are 3 as the molecule is symmetrical and contains 2 chiral carbon atoms.

Number of d and l isomers $= 2^{n - 1} = 2^{2 - 1} = 2$

Number of meso forms $= 2^{n / 2 - 1} = 2^{2 / 2 - 1} = 1$

Total number of stereoisomers $= 2 + 1 = 3$ .

Option B is correct.

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