Question

The total number of structural isomers of $C_3{H}_{6}B{r}_2$ is:

• A. $2$
• B. $4$
• C. $6$
• D. $3$

Answer 1

The correct option is B $4$

$Br$

(I) $C{H}_3-C{H}_2-CHB{r}_2$ (II) $C{H}_3-\underset{|}{CH}-C{H}_{2}Br$ (III) $C{H}_3-\underset{|}{\stackrel{|}{C}}-C{H}_3$ (IV)$Br-C{H}_2-C{H}_2-C{H}_2-Br$

$Br$ $Br$

Therefore the total number of structural isomers of $C_3{H}_{6}B{r}_2$ is $4$ .