The total number of tangents through the point (3,5) that can be drawn to the ellipses 3x2+5y2=32 and 25x2+9y2=450 is
A
0
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B
2
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C
3
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D
4
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Solution
The correct option is D3 Let S1=3x2+5y2−32 and S2=25x2+9y2−450 At point (3,5) S1=3(3)2+5(5)2−32=120>0 and S2=25(3)2+9(5)2−450 =225+225−450 =0 ∴ Point (3,5) lies outside the first ellipse and for second ellipse lies on the ellipse. Hence, two tangents for the first ellipse and one tangent for second ellipse can be drawn.