The total number of terms in the expansion of ((1+x2/3)(1+x4/3−x2/3))2021 is
A
4043
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B
3033
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C
2022
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D
2021
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Solution
The correct option is C2022 Given : ((1+x2/3)(1+x4/3−x2/3))2021
Let a=1 and b=x2/3
Then the expression becomes ((a+b)(a2+b2−ab))2021 =(a3+b3)2021 =(1+x2)2021 ∴ Total number of terms =2021+1=2022