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Question

The total number of terms in the expansion of ((1+x2/3)(1+x4/3x2/3))2021 is

A
4043
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B
3033
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C
2022
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D
2021
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Solution

The correct option is C 2022
Given : ((1+x2/3)(1+x4/3x2/3))2021
Let a=1 and b=x2/3
Then the expression becomes
((a+b)(a2+b2ab))2021
=(a3+b3)2021
=(1+x2)2021
Total number of terms =2021+1=2022

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