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Question

The total number of valence electrons in 4.2 g of N3 ion is (NA is the Avogardo's number)

A
2.1NA
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B
4.2NA
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C
1.6NA
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D
9.6NA
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Solution

The correct option is C 1.6NA
Molecular wt of N3=3×14=42 g
One ion of N3​ has valence electrons =3×5+1=16
42gN3=NAN3​ ion
valence electrons in NA​ ions = 16NA ​ (where NA ​ = Avogadro's number)
So, 1 g of N3 ​ will have valence electrons =16NA/42
therefore,4.2g of N3 ​ ion will have valence electrons =16NA×4.2/42=1.6NA
Option C is correct.

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