Question

The total number of ways in which a begger can be given at least one rupee from four $25$-paise coins, three $50$ paise coins and $2$ one-rupee coins, is

• A. $54$
• B. $50$
• C. $52$
• D. None of these

Answer 1

The correct option is A

$54$

Explanation for correct option

Number of ways of getting at least one rupee coin, random number of $50$-paise coin, random number of $25$-paise coin $=2\times 4\times 5=40$

Number of ways of getting at least two $50$-paise coins, random number of $25$-paise coins $=2\times 5=10$

Number of ways of getting one $50$-paise coin and at least two $25$-paise coin$=1\times 3=3$

Number of ways of getting four $25$-paise coins $=1$

Total number of ways $=40+10+3+1=54$

Hence, the correct option is $\left(\mathrm{A}\right)$