Question

The total number of ways in which a couple can sit around a table with $6$ guests if the couple takes consecutive seats is

• A. $1240$
• B. $1342$
• C. $1440$
• D. $1620$

Answer 1

The correct option is C $1440$

A couple and $6$ guests can be arranged
in $(7-1)!=6!$ ways and the couple can be arranged among themselves in $2!$ ways.

$\therefore$ The required number of ways
$=6!\times 2!=1440$