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Question

The total possible coordination isomers for the following compounds respectively are:
[Co(en)3][Cr(C2O4)3]
[Cu(NH3)4][CuCl4]
[Ni(en)3][Co(NO2)6].

A
4,4,4
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B
2,2,2
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C
2,2,4
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D
4,2,3
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Solution

The correct option is D 4,2,3
The complex [Co(en)3][Cr(C2O4)3] has four possible coordination isomers.
They are [Co(en)3][Cr(C2O4)3],[Co(C2O4)(en)2] and
[Cr(C2O4)2(en)],[Cr(C2O4)(en)2][Co(C2O4)2(en)],[Cr(en)3][Co(C2O4)3].

The complex [Cu(NH3)4][CuCl4] has two possible coordination isomers. They are [Cu(NH3)4][CuCl4],[CuCl(NH3)3][CuCl3(NH3)].

The complex [Ni(en)3][Co(NO2)6] has four possible coordination isomers.
They are [Ni(en)3][Co(NO2)6],[Ni(NO2)2(en)2][Co(NO2)4(en)] and [Co(NO2)2(en)2][Ni(NO2)4(en)],[Co(en)3][Ni(NO)2)6].

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