wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The total possible no. of roots of the equation 4x7+3x6+2x5+9x4+4x3+x2+9x+9=0 is

A
7.0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
7.00
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
7
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
07
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The given equation is 4x7+3x6+2x5+9x4+4x3+x2+9x+9=0.

This equation is of degree 7.

according to the fundamental theorem of algebra, an n degree equation will have a total of n roots.

the total no. of roots of this equation is 7.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Fundamental Theorem of Algebra
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon