The total pressure at the bottom of the container is given as - xH-L4 dg-P0- Find x atmospheric pressure -P0

Total pressure at the bottom of cylinder is P=weight of liquids+weight of cylinderA+P_0 P= [Ad (H2 )g+A2d (H2 )g ]+A5 (5/4d )LgA+P_0 P= (6H+L4 )dg ...

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Byju's Answer

Standard XII

Physics

Liquid Inside a U-Tube

The total pre...

Question

The total pressure at the bottom of the container is given as $= (\frac{x H + L}{4}) d g + P_{0}$ . Find $x$ (atmospheric pressure $= P_{0})$

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Solution

Total pressure at the bottom of cylinder is
$P = \frac{weight of liquids+weight of cylinder}{A} + P_{0}$
$P = \frac{[A d (\frac{H}{2}) g + A 2 d (\frac{H}{2}) g] + \frac{A}{5} (\frac{5}{4} d) L g}{A} + P_{0}$
$P = (\frac{6 H + L}{4}) d g + P_{0}$
Here we are asked to find the total pressure at the bottom of the container and not only the hydrostatic pressure; hence, we need to consider the total weight of liquid and cylinder in the container.

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The total pressure at the bottom of the container is given as =(xH+L4)dg+P0. Find x (atmospheric pressure =P0)

The total pressure at the bottom of the container is given as $= (\frac{x H + L}{4}) d g + P_{0}$ . Find $x$ (atmospheric pressure $= P_{0})$