Question

The total pressure exerted by a mixture of 4g of $O_2$ and 2g of $H_2$ confined in a bulb of 1 L at $O^{\circ }$ is –

• A. 25 atom
• B. 45 atom
• C. 15 atom
• D. 31 atom

Answer 1

The correct option is A

25 atom

No. of moles of $H_2=\frac{2}{2}=1mole$

No. of moles of $O_2=\frac{4}{32}=0.125mole$

Total moles of mixture =1.125 moles

PV = nRT (or) $P=\frac{nRT}{V}=\frac{1.125\times 0.082\times 273}{1}$

P = 25.184 atm