The total pressure exerted by the mixture of 7g of $N_{2}$ , 2g of $H_{2}$ and 8g of $S O_{2}$ gases in a vessel of 6L capacity kept at $27^{0} C$ is .

2.5 atm

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5.7 atm

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4.5 atm

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Solution

The correct option is B 5.7 atm
Number of moles of Nitrogen = $\frac{7}{28}$
= $\frac{1}{4}$ moles

Number of moles of Hydrogen = $\frac{2}{2}$
= 1mole

Number of moles of Sulphur dioxide = $\frac{8}{64}$
= $\frac{1}{8}$ moles

Total number of moles = $\frac{1}{4} + 1 + \frac{1}{8}$

= $\frac{11}{8}$ moles

Ideal gas equation is $P V = n R T$

$P = \frac{n R T}{V}$

$P = \frac{11}{8} \times \frac{0.0821 \times 300}{6}$

$P = 5.7 a t m$

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The total pressure exerted by the mixture of 7g of N2, 2g of H2 and 8g of SO2 gases in a vessel of 6L capacity kept at 270C is .

The correct option is B 5.7 atmNumber of moles of Nitrogen = 728 = 14 moles Number of moles of Hydrogen = 22 = 1mole Number of moles of Sulphur dioxide =864 = 18 moles Total number of moles = 14+1+18 = 118 moles Ideal gas equation is PV = nRT P = nRTV P = 118×0.0821×3006 P = 5.7 atm

The total pressure exerted by the mixture of 7g of $N_{2}$ , 2g of $H_{2}$ and 8g of $S O_{2}$ gases in a vessel of 6L capacity kept at $27^{0} C$ is .