The total revenue $R = 720 x - 3 x^{2}$ where $x$ is the number of items sold. Find $x$ for which total revenue $R$ is increasing.

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Solution

$R = 720 x - 3 x^{2}$
$∴$ The value of x for which R will increase is given by x for which $\frac{d R}{d x} > 0$

$\frac{d R}{d x} = 720 - 6 x$

$720 - 6 x > 0$

$720 > 6 x$

$x < 120$

For $x < 120$ , the revenue is increasing.

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The total revenue R=720x−3x2 where x is the number of items sold. Find x for which total revenue R is increasing.

R=720x−3x2∴The value of x for which R will increase is given by x for which dRdx>0dRdx=720−6x 720−6x>0 720>6x x<120For x<120, the revenue is increasing.

The total revenue $R = 720 x - 3 x^{2}$ where $x$ is the number of items sold. Find $x$ for which total revenue $R$ is increasing.

$R = 720 x - 3 x^{2}$
$∴$ The value of x for which R will increase is given by x for which $\frac{d R}{d x} > 0$

$\frac{d R}{d x} = 720 - 6 x$

$720 - 6 x > 0$

$720 > 6 x$

$x < 120$

For $x < 120$ , the revenue is increasing.