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Quantum Number

The total spi...

Question

The total spin and magnetic moment for the atom with atomic number 24 are:

\pm

\sqrt{48}

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\pm

\sqrt{35}

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\pm

\frac{3}{2}

\sqrt{48}

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\pm

\frac{3}{2}

\sqrt{35}

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Solution

The correct option is B $\pm$ 3, $\sqrt{48}$ BM
Atomic number $= 7$
$3 d^{5} 4 s^{1}$
Total spin $= \pm \frac{1}{2} \times = \pm 3$
Magnetic moment = $\sqrt{n (n + 2)}$ = $\sqrt{6 (6 + 2)}$ = $\sqrt{48}$

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Similar questions

\begin{matrix} Column-I & Column-II a . & C o^{3 +} & i . & \sqrt{8} B M b . & C r^{3 +} & i i . & \sqrt{35} B M c . & F e^{3 +} & i i i . & \sqrt{3} B M d . & N i^{2 +} & i v . & \sqrt{24} B M v . & \sqrt{15} B M \end{matrix}

C e^{3 +}

C e

x^{3 +}

\sqrt{35}

x

F e

[F e (C N)_{6}]^{3 -}

[C r (N H_{3})_{6}]^{3 +}

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C u

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29

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