The total surface area of a cube is $96 c m^{2}$ . The volume of the cube is:

8 c m^{3}

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512 c m^{3}

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64 c m^{3}

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27 c m^{3}

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Solution

The correct option is B $64 c m^{3}$
Let $^{'} e^{'}$ be the edge of cube.
Surface area of cube is $6 (e)^{2}$
Given is the surface area of cube is $96 c m^{2}$
$96 = 6 e^{2}$
$e^{2} = 16$
$∴ e = 4$ cm
Volume of cube= $e^{3} = 64 c m^{2}$

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The total surface area of a cube is $96 c m^{2}$ . The volume of the cube is:

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