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Surface Area of a Frustum

The total sur...

Question

The total surface area of a frustum of cone is calculated by using the formula _________.

2 π [R^{2} + r^{2} + l (R + r)]

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π [R^{2} + r^{2} + l (R + r)]

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R^{2} + r^{2} + l (R + r)

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π [R^{2} + r^{2} + l (R - r)]

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Solution

The correct option is B $π [R^{2} + r^{2} + l (R + r)]$
Area of slanted surface $= π l (r + R)$
Area of base circle of frustum $= π R^{2}$

Area of top circle of frustum $= π r^{2}$

Total surface area $= π [R^{2} + r^{2} + l (R + r)]$

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Similar questions

π l (r_{1} + r_{2}) + π {r_{1}}^{2} + π {r_{2}}^{2}

r_{1}

r_{2}

R

M

F_{1}

F_{2}

△ A B C

a < b < c

r

r_{1}, r_{2}, r_{3}

A, B, C

r < r_{1} < r_{2} < r_{3}

△ A B C, r_{1} r_{2} + r_{2} r_{3} + r_{3} r_{1} = \frac{r_{1} r_{2} r_{3}}{r}

R_{1} + R_{2} = R

R_{1} + R_{2} < R

R_{1}^{2} + R_{2}^{2} < R^{2}

R_{1}^{2} + R_{2}^{2} = R^{2}

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