Question

The total surface area of a solid right circular cylinder is $660sq.cm$. If its diameter of the base is $14cm$, find the height of the cylinder.

Answer 1

We have,

$TSA=660c{m}^2$

$d=2r=14cm$

$r=7cm$

We know that the total surface area of the cylinder

$=2\pi rh+2\pi r^2$

So,

$2\pi rh+2\pi r^2=660$

$2\times \frac{22}{7}\times 7\times h+2\times \frac{22}{7}\times 7^2=660$

$2\times 22\times h+2\times 22\times 7=660$

$44\times h+44\times 7=660$

$44(h+7)=660$

$h+7=15$

$h=8cm$

Hence, this is the answer.