The total surface area of a solid right circular cylinder whose radius is half of its height $h$ is equal to

\frac{3}{2} π h

sq. units

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\frac{2}{3} π h^{2}

sq. units

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\frac{3}{2} π h^{2}

sq. units

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\frac{2}{3} π h

sq. units

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Solution

The correct option is D $\frac{3}{2} π h^{2}$ sq. units
We have,
$h = h, r = \frac{h}{2}$

We know that the total surface area of the cylinder
$= 2 π r (h + r)$

So,
$= 2 π \times \frac{h}{2} (h + \frac{h}{2})$

$= π \times h (\frac{3 h}{2})$

$= \frac{3}{2} π h^{2} s q . u n i t s$

Hence, this is the answer.

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The total surface area of a solid right circular cylinder whose radius is half of its height h is equal to

The correct option is D 32πh2 sq. unitsWe have,h=h,r=h2We know that the total surface area of the cylinder=2πr(h+r)So,=2π×h2(h+h2)=π×h(3h2)=32πh2 sq. unitsHence, this is the answer.

The total surface area of a solid right circular cylinder whose radius is half of its height $h$ is equal to