The total value of $m_{s}$ for all electrons in $N$ atom is:

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Solution

$N$ configuration is $1 s^{2} 2 s^{2} 2 p^{3}$
So $1 s^{2}$ orbital have 2 electrons one have $m_{s}$ value -1/2 and other have +1/2
$2 s^{2}$ orbital have 2 electrons one have $m_{s}$ value -1/2 and other have +1/2
$2 p^{3}$ orbital have 3 electrons and all have $m_{s}$ valuecan be -1/2 or +1/2

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n = 4,

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In an atom, the total number of electrons having quantum number
$n = 4, | m_{l} | = 1 a n d m_{s} = - \frac{1}{2} i s$ ___

n = 4, | m_{l} | = 1

m_{s} = - \frac{1}{2}

n = 4, | m_{l} | = 1

m_{s} = - \frac{1}{2}

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