The total vibrational energy of a particle in SHM is E. Its kinetic energy at half the amplitude from mean position will be :
A
E/2
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B
E/3
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C
E/4
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D
3E/4
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Solution
The correct option is D3E/4 Total vibrational energy(E), E=12mω2A2 KE=12mω2(A2−x2) ⇒KE=12mω2(A2−A24) (∵x=A/2) ⇒KE=34(12mω2A2)=3E4
Hence, option (d) is the correct answer.