Question

The total weight of a piece of wood is 6 kg. In the floating state in water, its $\frac{1}{3}$ part remains inside the water. On this floating solid, what maximum weight is to be put such that whole of the piece of wood is drowned in the water?

• A. 12 kg
• B. 10 kg
• C. 14 kg
• D. 15 kg

Answer 1

The correct option is A 12 kg

$6=\frac{V}{3}{\rho }_w\left(1\right)V{\rho }_w=18V{\rho }_B=6$

Let body of mass $m$is placed on it.

$(6+m)=V{\rho }_{w}6+m=18m=12kg$