Question

The total weight of a piece of wood is 6 kg in the floating state in water its $\frac{1}{3}$ part remains inside the water. On this floating solid, what maximum mass is to be put such that the whole of the piece of wood is to be drowned in the water :-

• A. 12 kg
• B. 10 kg
• C. 14 kg
• D. 15 kg

Answer 1

The correct option is A 12 kg

Block's weight is supported by V/3 volume of water
$⟹6=V/3\times d$ (d is density of water)
$⟹V\times d=18kgs$
Therefore for the complete volume to be immersed $W=18-6=12kgs$ weight should be placed