The trace of a square matrix is defined as the sum of the principal diagonal elements. For real numbers a and b, if the trace of matrices A=[2a2539−6b] and B=[−b2238a−8] are equal, then 2a−b is equal to
A
0
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B
1
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C
2
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D
4
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Solution
The correct option is B1 From given matrices, Tr(A)=2a2+9−6b
and Tr(B)=−b2+8a−8
Given, Tr(A)=Tr(B) ⇒2a2+9−6b=−b2+8a−8⇒2(a2−4a+4)+(b2−6b+9)=0⇒2(a−2)2+(b−3)2=0 ⇒a−2=0 and b−3=0 ⇒a=2,b=3
So, 2a−b=1