wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The train is approaching station with 72 kmh1. When 1 km away it blows a whistle of frequency 600 Hz. The frequency heard by the person is (vsound=350ms1)

A
612 Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
625 Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
636 Hz
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
none of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 636 Hz
Let the original frequency of the source fo=600 Hz.
Velocity of train Vtrain=72×518=20 m/s
Using Doppler effect when a source is moving towards stationary observer,
Apparent frequency heard f=fo[VsoundVsoundVtrain]
f=600[35035020]
f=636 Hz
So, option C is correct.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Doppler's Effect
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon