The trajectory of a projectile is given by the equation y=x−x2. What is the value of the initial velocity and the angle of projection?
A
√10m/s,30∘
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B
10m/s,45∘
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C
√10m/s,45∘
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D
10m/s,30∘
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Solution
The correct option is C√10m/s,45∘ The equation of a projectile is given by y=xtanθ−12gx2u2cos2θ. Comparing the standard equation with the given equation y=x−x2, we get tanθ=1 ⇒θ=tan−1(1)=45∘ Also, 12gu2cos2θ=1 ⇒1210u2cos245∘=1 ⇒1210×2u2=1 ⇒u=√10m/s