CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The trajectory of the projectile near the surface of the earth is given as y=2x9x2. If it was launched at an angle θ0 with speed v0 then (g=10 m/s2)

A
θ0=sin115 and v0=35 ms1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
θ0=cos125 and v0=35 ms1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
θ0=cos115 and v0=53 ms1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
θ0=sin125 and v0=35 ms1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C θ0=cos115 and v0=53 ms1
Given, y=2x9x2

On comparing with,

y=xtanθgx22v20cos2θ

We have,
tanθ=2 or cosθ=15 [cosθ=11+tan2θ]

And, g2v20cos2θ=9

102v20(1/5)2=9

v0=53 m/s

Hence, (C) is the correct answer.

flag
Suggest Corrections
thumbs-up
35
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Relative Motion
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon