The trans-alkenes are formed by the reduction of alkynes with

H_{2} - P d / C, B a S O_{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

S n - H C l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

N a / l i q . N H_{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

N a B H_{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $N a / l i q . N H_{3}$
Sodium metal in liquid ammonia reduces alkynes with anti stereochemistry to give trans alkenes. The reduction is selectively anti since the vinyl radical formed during reduction is more stable in trans configuration.Sodium atom donates an electron to alkyne which after $H - abstraction$ from $N H_{3}$ forms vinylic radical. Transfer of another electron gives a vinylic anion, which is more stable in trans form. This in turn gives trans-alkene after $H - abstraction$ from $N H_{3}$

Suggest Corrections

Similar questions

Alkynes on reduction form trans alkenes in presence of:

2

N H_{3}

Join BYJU'S Learning Program