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Introduction to Transistor

The transfer ...

Question

The transfer characteristic curve for a based transistor is common-emitter configuration is shown in figure where $v_{0}$ represents output voltage and $v_{1}$ is input voltage. For the action of transistor as amplifier.

A

Region I of graph is used

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B

Region II of graph is used

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C

Region III of graph is used

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D

Both regions I and III are used

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Solution

The correct option is B Region II of graph is used
Region (I) is the cut-off region, region (II) is the active region and region (III) is the saturation region.
The region (II) of transfer characteristic is an active region and hence it is used as an amplifier. So, option (B) is correct.

(If we use a transistor as a switch, the cut off region (I) is used for OFF state and the saturation region (III) is used for ON state)

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] for a base blased transistor in CE configuration is as shown in the figure For using transistor as a switch it is used:

Q. Transfer characteristics [output voltage

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Q. Find out the graph which shows the input, transfer and output characteristic curve of a transistor in common configuration?

Q. Draw the typical input and output characteristics of an n-p-n transistor in CE configuration. Show how these characteristics can be used to determine (a) the input resistance

(r_{i})

, and (b) current amplification factor

β

.

Input charcteristics: It is the graph drawn between input current and input voltage when output voltage is kept constant.

Output characteristics : It is the graph drawn between output current and output voltage when input current is kept constant.

(a) Input resitance

(R_{i}

= {[\frac{Change in emitter base voltage (△ V_{B E})}{Change in base current (△ I_{B})}]}_{at constant V_{C E}}

R_{i} = {(\frac{△ V_{B E}}{△ I_{B}})}_{V_{C E}}

(b) Current amplification factor,

(β) = {(\frac{△ I_{C}}{△ I_{B}})}_{V_{C E}}

\frac{△ I_{C}}{△ I_{E} - △ I_{C}}

\frac{\frac{△ I_{C}}{△ I_{E}}}{\frac{△ I_{C}}{△ I_{E}} - \frac{△ I_{C}}{△ I_{E}}}

\frac{α}{1 - α}

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