Question

The transfer ratio $\beta$ of a transistor is $50$. The input resistance of the transistor, when used in the common emitter configuration is $1k\Omega$. The peak value of the collector A.C current for an A.C input voltage of $0.01V$, is :

• A. $500\mu A$
• B. $0.25\mu A$
• C. $0.01\mu A$
• D. $100\mu A$

Answer 1

The correct option is A $500\mu A$

$\beta =\frac{I_c}{I_b}$ $\Rightarrow$ $I_b=\frac{0.01}{1\times {10}^{-5}}$
or $50=\frac{I_c}{{10}^{-5}}$ $\Rightarrow$ $I_c=50\times {10}^{-5}$
$=500\times {10}^{-6}$
$I_c=500\mu A$