Question

The transfer ratio $\beta$ of transistor is $50$. The input resistance of a transistor when used in C.E. (Common Emitter) configuration is 1K$\Omega$. The peak value of the collector A.C current for an A.C input voltage of $0.01V$ peak is

• A. $100\mu A$
• B. $0.01mA$
• C. $0.25mA$
• D. $500\mu A$

Answer 1

The correct option is D $500\mu A$

[Hint $\Rightarrow i_B=\frac{V_s}{R_{in}}=\frac{0.01}{{10}^3}=1\times {10}^{-5}$ A
Now $\beta$ of transistor is defined as ${\beta }_{ac}=\frac{i_c}{i_b}$
or $i_c=50\times {10}^{-5}=500\mu A$ ]