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Question

The transfer ratio of a transistor is 50. The input resistance of the transistor when used in the common-emitter configuration is 1 kΩ. The peak value of the collector AC current for an AC input voltage of 0.01 V peak is (in μ m)

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Solution

β=50, Ri=1000 Ω,
Vi=0.01 Vβ=icRb,
ib=Vi/Ri=0.01/103=105A
ic=50×105A=500 μA

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