Question

The transfer ratio of a transistor is 50. The input resistance of the transistor when used in the common-emitter configuration is 1 kΩ. The peak value of the collector AC current for an AC input voltage of 0.01 $V$ peak is (in $\mu m$)

Answer 1

β=50, $R_i=1000\Omega ,$
$Vi=0.01V_{\beta }=i_c{R}_b,$
$i_b=V_i/R_i=0.01/{10}^{-3}={10}^{-5}A$
$i_c=50\times {10}^{-5}A=500\mu A$