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Byju's Answer
Standard XII
Physics
Introduction
The transform...
Question
The transformed equation of
x
4
+
4
x
3
+
2
x
2
−
4
x
−
2
=
0
by eliminating second term is
A
x
4
+
4
x
2
+
1
=
0
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B
x
4
+
4
x
2
−
1
=
0
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C
x
4
−
4
x
2
+
1
=
0
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D
x
4
−
2
x
2
+
1
=
0
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Solution
The correct option is
C
x
4
−
4
x
2
+
1
=
0
Here, second term is nothing but
x
3
h
=
−
a
4
n
a
3
Substitute
x
=
y
+
h
x
=
y
−
1
x
4
−
4
x
2
+
1
=
0
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0
Similar questions
Q.
Remove the second term from the equation:
x
4
+
4
x
3
+
2
x
2
−
4
x
−
2
=
0
.
Q.
The roots equation
x
4
−
3
x
3
+
4
x
2
−
3
x
+
1
=
0
is
Q.
Solve the reciprocal equation
x
4
−
3
x
3
+
4
x
2
−
3
x
+
1
=
0
Q.
Evaluate the following:
(i)
2
x
3
+
2
x
2
-
7
x
+
72
,
when
x
=
3
-
5
i
2
(ii)
x
4
-
4
x
3
+
4
x
2
+
8
x
+
44
,
when
x
=
3
+
2
i
(iii)
x
4
+
4
x
3
+
6
x
2
+
4
x
+
9
,
when
x
=
-
1
+
i
2
(iv)
x
6
+
x
4
+
x
2
+
1
,
when
x
=
1
+
i
2
.
Q.
The transformed equation of
x
4
+
8
x
3
+
x
−
5
=
0
by eliminating second term is:
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