The transformed equation of $x^{4} + 4 x^{3} + 2 x^{2} - 4 x - 2 = 0$ by eliminating second term is

x^{4} + 4 x^{2} + 1 = 0

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x^{4} + 4 x^{2} - 1 = 0

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x^{4} - 4 x^{2} + 1 = 0

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x^{4} - 2 x^{2} + 1 = 0

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Solution

The correct option is C $x^{4} - 4 x^{2} + 1 = 0$
Here, second term is nothing but $x^{3}$
$h = - \frac{a_{4}}{n a_{3}}$
Substitute $x = y + h$
$x = y - 1$
$x^{4} - 4 x^{2} + 1 = 0$

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