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Heating Effect of Current

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Question

The transformer with efficiency 80%works at 4kw and 100V. If the secondary voltage is 200 V then the primary and secondary currents are respectively?

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Solution

given n=80%
Ep=100v
EpIp=4kw
=4000w
Ip=Ep.Ip/Ep
=4×1000/100
=40A
Is=80×100×40/200×100
=16 A

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