The transition elements have characteristic electronic configuration which can be represented as:

(n-1)s²p⁶d¹⁰ ns²np⁶nd^1-10

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(n-2) d^{1 – 10}(n-1) s²p⁶d^{1 or 2} ns¹

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(n-1) d^1-10 ns^0-2

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(n-2) d^{1 – 10}(n-1) p⁶ns²

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Solution

The correct option is C
(n-1) d^1-10 ns^0-2

In transition elements, there is filling of d orbitals in the penultimate shell.

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Similar questions

d^{1 \to 10} n s^{1 \to 2}

The outer electron configuration of first transition series is ${(n - 1) d}^{1 - 10} {n s}^{1 - 2}$ . Then value of $n$ is:

^{1 - 10}

^{1 - 2}

n s^{2} (n - 1) d^{1 - 10} (n - 2) f^{1 - 14}

1, d_{1}, d_{2}, d_{3} \dots, d_{n - 1}

n^{t h}

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