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Question

# The transition from state n = 4 to n = 3 in a He+ ion result in ultraviolet radiation. Infrared radiation will be obtained in the transition from

A

n=2n=1

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B

n=3n=2

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C

n=5n=4

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D

n=8n=6

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Solution

## The correct option is D n=8→n=6 In case of H-spectrum UV spectrum appears from n1=1, to n2=2,3.... Here in case of He+ spectrum UV spectrum is from n1 to n2=4. ¯νUV=RZ2(132−142)R×4(132−142) In case of H-spectrum IR appears from n1=3, n2=4,5.... ¯νIR for H+2=R×12(132−142) .....(i) ¯νIR for He+=R×4(1n21−1n22)=R(4n21−4n22) .....(ii) Comparing the coefficient of equation (i) and (ii), we get 4n21=19;n1=6 4n21=116;n2=8 Thus, transition for He+ in IR is n1→6 to n2→8. Note: IR region starts with n1=3.

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