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The transition from state n = 4 to n = 3 in a He+ ion result in ultraviolet radiation. Infrared radiation will be obtained in the transition from


A

n=2n=1

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B

n=3n=2

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C

n=5n=4

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D

n=8n=6

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Solution

The correct option is D

n=8n=6


In case of H-spectrum UV spectrum appears from n1=1, to n2=2,3....
Here in case of He+ spectrum UV spectrum is from n1 to n2=4.

¯νUV=RZ2(132142)R×4(132142)

In case of H-spectrum IR appears from n1=3, n2=4,5....

¯νIR for H+2=R×12(132142) .....(i)

¯νIR for He+=R×4(1n211n22)=R(4n214n22) .....(ii)

Comparing the coefficient of equation (i) and (ii), we get
4n21=19;n1=6
4n21=116;n2=8

Thus, transition for He+ in IR is n16 to n28.
Note: IR region starts with n1=3.


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