The transition from the state n = 4 to n = 3 in a hydrogen-like atom results in ultra violet radiation. Infrared radiation will be obtained in the transition. (IIT-JEE-2001)

2 \to 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3 \to 2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4 \to 2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5 \to 4

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $5 \to 4$
Infrared radiation has a higher wavelength and hence lower energy as compared to the ultraviolet radiation. So, a transition with energy difference less than the n=4 to n=3 transition will result in infrared. Looking at the options, n=5 to n=4 is the correct answer.

Suggest Corrections

Similar questions

The transition from the state n = 4 to n = 3 in a hydrogen-like atom results in ultra violet radiation. Infrared radiation will be obtained in the transition. (IIT-JEE-2001)

Q. The transition from the state n = 4 to n = 3 in a hydrogen like atom results in ultraviolet radiation. Infrared radiation will be obtained in the transition.

The transition from the state n = 3 to n = 1 in a hydrogen like atom results in ultraviolet radiation. Infrared radiation will be obtained in the transition from

Q. The transition from from the state

n = 5

n = 1

in a hydrogen atom results in

U V

radiation. Infrared radiation will be obtained in the transition.

Join BYJU'S Learning Program

The transition from the state n = 4 to n = 3 in a hydrogen-like atom results in ultra violet radiation. Infrared radiation will be obtained in the transition. (IIT-JEE-2001)

The correct option is D 5→4Infrared radiation has a higher wavelength and hence lower energy as compared to the ultraviolet radiation. So, a transition with energy difference less than the n=4 to n=3 transition will result in infrared. Looking at the options, n=5 to n=4 is the correct answer.