The transition metal ions responsible for color in Ruby and Emerald are, respectively :

{C o}^{3 +}

and

{C r}^{3 +}

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{C o}^{3 +}

and

{C o}^{3 +}

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{C r}^{3 +}

and

{C r}^{3 +}

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{C r}^{3 +}

and

{C o}^{3 +}

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Solution

The correct option is B ${C r}^{3 +}$ and ${C r}^{3 +}$
Ruby is ${A l}_{2} O_{3}$ in which Red colour is obtained when $C r^{+ 3}$ is replacing ${A l}^{+ 3}$ ions in octahedral sites.

Emerald is ${B e}_{3} {A l}_{2} {(S i O_{3})}_{6}$ in which green colour is obtained when ${C r}^{+ 3}$ is replacing ${A l}^{+ 3}$ in octahedral site.

Hence, the correct option is $C$ .

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Similar questions

Calculate the potential of the following cell :

$E_{C o^{2 +} | C O^{3 +}}^{⊖} = - 2 V, E_{C r_{2} O_{7}^{2 -} | C r^{3 +}}^{⊖} = + 1.0 V$

$P t ∣ ∣ ∣ \begin{matrix} C o^{2 +}, C o^{3 +} (2.0 M) (1.0 M) \end{matrix} ∣ ∣ ∣ \begin{matrix} C r^{3 +}, C r_{2} O_{7}^{2 -}, H^{\oplus} (1.0 M) (4.0 M) (1.0 M) \end{matrix} ∣ ∣ ∣ P t$

Q. Which of the following species would you expect to be diamagnetic?

K^{+}, C r^{3 +}, Z n^{2 +}, C d, C o^{3 +}, S n^{2 +}

Q. What is the number of total isomers including stereoisomers that have the formula

C o C r (N H_{3})_{6} C l_{6}

. (All are ionic salts that have

C o^{3 +}

and

C r^{3 +}

as central atoms with octahedral geometry and

N H_{3}

and

C l^{-}

as ligands)

Q. Match the metal ions given in Column I with the spin magnetic moments of the ions given in Column II and assign the correct code :

	Column I		Column II
a.	$C o^{3 +}$	i.	$\sqrt{8} B . M .$
b.	$C r^{3 +}$	ii.	$\sqrt{35} B . M .$
c.	$F e^{3 +}$	iii.	$\sqrt{3} B . M .$
d.	$N i^{2 +}$	iv.	$\sqrt{24} B . M .$
		v.	$\sqrt{15} B . M .$

\begin{matrix} Column - 1 & Column - 2 S p e c i e s & C h a r a c t e r i s t i c s (A) C o^{3 +} (Z = 27) & (p) Total number of fully filled orbitals is nine. (B) S c^{3 +} (z = 21) & (q) The value of magnetic moment (spin only) is greater than or equal to 3.87 BM. (C) C r^{3 +} (Z = 24) & (r) Number of electrons with n + l = 3 is eight. (D) N i^{2 +} (Z = 28) & (s) Number of electrons with (m = 0) may be either 11 or 12. (t) No unpaired electron. \end{matrix}

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The transition metal ions responsible for color in Ruby and Emerald are, respectively :

The correct option is B Cr3+ and Cr3+Ruby is Al2O3 in which Red colour is obtained when Cr+3 is replacing Al+3 ions in octahedral sites. Emerald is Be3Al2(SiO3)6 in which green colour is obtained when Cr+3 is replacing Al+3 in octahedral site.Hence, the correct option is C.