Question

The transition of electron in H-atom that will emit maximum energy is:

• A. $n_3\to n_2$
• B. $n_4\to n_3$
• C. $n_5\to n_4$
• D. all have same energy

Answer 1

Answer: (A)

$n_3\to n_2$

Energy is given by formula
$E=\frac{hc}{\lambda }$

$\frac{1}{\lambda }=R{Z}^2[\frac{1}{n_1^2}-\frac{1}{n_2^2}]$

$E=R{Z}^{2}hc[\frac{1}{n_1^2}-\frac{1}{n_2^2}]$

This energy will be highest when the transition is from $n_3\to n_2$.