The transmitter and the receiver are now pulled up into air. The air is blowing with a speed 5 m/s in the direction opposite the river stream. Determine the frequency of the sound detected by the receiver
A
200698 Hz
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B
100698 Hz
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C
300698 Hz
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D
400698 Hz
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Solution
The correct option is A100698 Hz Velocity of sound in still air (Vsa)=(γRT/M)1/2=344m/s. f′=f(Vsa−Va)/(Vsa−Va−Vb)=100698 Hz. Here va= velocity of air.