The magnetic induction at a point P which is distant 4 cm from a long current carrying wire is $10^{- 3}$ Telsa.The field of induction at a distance 12 cm from the same current would be

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The transmitting antenna of a radio station is mounted vertically. At a point 10km due north of the transmitter the peak electric field is 10−3V/m. The magnitude of the radiated magnetic field is:

The correct option is B 3.33×10−12TB0=E0cE0 - Electric field, c - speed of light, B0 - Magnetic field.B0=10−33×108=3.33×10−12T

The transmitting antenna of a radio station is mounted vertically. At a point $10 k m$ due north of the transmitter the peak electric field is $10^{- 3} V / m$ . The magnitude of the radiated magnetic field is:

The correct option is B $3.33 \times 10^{- 12} T$
$B_{0} = \frac{E_{0}}{c}$
$E_{0}$ - Electric field, $c$ - speed of light, $B_{0}$ - Magnetic field.
$B_{0} = \frac{10^{- 3}}{3 \times 10^{8}} = 3.33 \times 10^{- 12} T$