The transverse displacement y x - t of a wave on a string is given by -y x - t - e ax 2- bt 2-2 - ab xt - This represent-A- wave moving in -x direction with speed -a-bB- wave moving in -x direction with speed -b-aC- standing wave of frequency -bD- standing wave of frequency 1- b

The correct option is B wave moving in +x direction with speed √(b/a)y(x,t ) = e^(√(ax) + √(bt) )^2 v = ω/k = √(b)/√(a) = √(b/a) ...

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Standard XII

Physics

Displacement Current

The transvers...

Question

The transverse displacement y(x, t) of a wave on a string is given by $y (x, t) = e^{(a x^{2} + b t^{2} + 2 \sqrt{a b} x t)}$ . This represent :

wave moving in +x direction with speed

\sqrt{\frac{a}{b}}

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wave moving in +x direction with speed

\sqrt{\frac{b}{a}}

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standing wave of frequency

\sqrt{b}

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standing wave of frequency

\frac{1}{\sqrt{b}}

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Solution

The correct option is B wave moving in +x direction with speed $\sqrt{\frac{b}{a}}$
$y (x, t) = e^{{(\sqrt{a x} + \sqrt{b t})}^{2}} v = \frac{ω}{k} = \frac{\sqrt{b}}{\sqrt{a}} = \sqrt{\frac{b}{a}}$

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The transverse displacement y(x, t) of a wave on a string is given by y(x,t)=e(ax2+bt2+2√abxt). This represent :

The correct option is B wave moving in +x direction with speed √bay(x,t)=e(√ax+√bt)2v=ωk=√b√a=√ba

The transverse displacement y(x, t) of a wave on a string is given by $y (x, t) = e^{(a x^{2} + b t^{2} + 2 \sqrt{a b} x t)}$ . This represent :

The correct option is B wave moving in +x direction with speed $\sqrt{\frac{b}{a}}$
$y (x, t) = e^{{(\sqrt{a x} + \sqrt{b t})}^{2}} v = \frac{ω}{k} = \frac{\sqrt{b}}{\sqrt{a}} = \sqrt{\frac{b}{a}}$