Question

The trapezoid is divided into a rectangle and two triangles as shown in the above figure. Find the combined area of the two shaded triangles. ( All lengths are in inches)

• A. $4$
• B. $6$
• C. $9$
• D. $12$
• E. $14$

Answer 1

The correct option is C $9$

The base of the triangles is $=\frac{1}{2}\times (12-6)=3$.

Hence the two triangles are right angles isosceles as base and height are both equal to $3$ units.

Area of one triangle $=\frac{1}{2}\times Base\times Height=\frac{1}{2}\times 3\times 3=\frac{9}{2}sq.units$
Therefore, the required area is $2\times ($ Area of the triangle $)$$=2\times \frac{9}{2}\text{sq. units}$
$=9sq.units$