Question

The travel graph of John and Kate is shown.

At what time did the distance travelled by Kate equal the distance travelled by John?

• A. $12$ pm
• B. $11:15$ am
• C. $11:30$ am
• D. $10:30$ am

Answer 1

The correct option is B $11:15$ am

In given graph John's starting and ending point are $(9,0)$ and $(12,20)$

Equation of John

$y=\frac{20-0}{12-9}(x-9)$

$y=\frac{20}{3}(x-9)$

$3y=20x-180$

Hence kate and John both are meeting at point $(x,15)$

Then passing John through $(x,15)$

$45=20x-180$

$225=20x$

$x=11.25$

In time zone $.25unit=.15timeunit$

Converting $x$ into time zone

$x=11:15am$