The treatment of CH 32 C - CHCH 3 with boiling KMnO 4 produces-A- CH 3 COCH 3- CH 3 COCH 3B- CH 3 CHO - CO 2C- CH 3 COCH 3 onlyD- CH 3 COCH 3- CH 3 CHO

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Addition Reactions

The treatment...

Question

The treatment of $(C H_{3})_{2} C = C H C H_{3}$ with boiling $K M n O_{4}$ produces :

C H_{3} C O C H_{3} + C H_{3} C O C H_{3}

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C H_{3} C O C H_{3} + C H_{3} C H O

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C H_{3} C H O + C O_{2}

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C H_{3} C O C H_{3}

only

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Solution

The correct option is B $C H_{3} C O C H_{3} + C H_{3} C H O$
$K M n O_{4}$ acts as a strong oxidising agent oxidises the double bond to give acetone and acetaldehyde as a product.

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X,Y and Z are three organic compounds. All the three undergo iodoform test .Only Y and Z can react with 2,4 -DNP. Only Z can reduce tollen's reagent. Here X,Y and Z respectively

Q. Write the product of the following reactions :
(i)

C H_{3} C O C H_{3} Z a - H g - ----- \to c o n c . H C I

(ii)

C H_{3} C O_{C} H_{3} (a) M g - H g d r y o t h e r - ----------------- \to (b) d i l . a c i d

(iii)

C H_{3} C O_{2} H (a) B r_{2} + r e d P - --------- \to (b) H_{2} O

(iv)

C H_{3} C H O H C N - -- \to

(v)

(H C O O H)_{2} C a d r y d i s t i l l a t i o n - --------- \to

C H_{3} C H O

and

C H_{3} C O C H_{3}

can not be distinguished by :-

C H_{3} C H O

and

C H_{3} C O C H_{3}

can not be extinguished by:-

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Addition Reactions

Standard XII Chemistry

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The treatment of (CH3)2C=CHCH3 with boiling KMnO4 produces :

The correct option is B CH3COCH3+CH3CHOKMnO4 acts as a strong oxidising agent oxidises the double bond to give acetone and acetaldehyde as a product.

The treatment of $(C H_{3})_{2} C = C H C H_{3}$ with boiling $K M n O_{4}$ produces :

The correct option is B $C H_{3} C O C H_{3} + C H_{3} C H O$
$K M n O_{4}$ acts as a strong oxidising agent oxidises the double bond to give acetone and acetaldehyde as a product.