The treatment of CH3MgX with CH-CH produces-

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Synthesis by Reduction of Nitriles

The treatment...

Question

The treatment of $C H_{3} M g X$ with $C H \equiv C H$ produces:

C H_{4}

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C H_{3} - C H = C H_{2}

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C H_{3} - C \equiv C - C H_{3}

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C H_{3} - C H = C H - C H_{3}

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Solution

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C H_{3} M g X

C H_{3} - C \equiv C - H

A . C H_{3} - C H = C H_{2} + H C l ⟶ C H_{3} - C | C l H - C H_{3}

B . C H_{3} - C H = C H_{2} + H B r ⟶ C H_{3} - C H_{2} - C H_{2} B r

C . C H_{3} - C H = C H_{2} + H B r p e r o x i d e - ---- \to C H_{3} - C H_{2} - C H_{2} - B r

D . C H_{3} - C H = C H_{2} + H I p e r o x i d e - ---- \to C H_{3} - C | I H - C H_{3}

A g N O_{3}

C H_{3} - C H_{3}, C H_{2} = C H_{2}

C H \equiv C H

{CH}_{3} - {CH}_{2} - CH = {CH}_{3}

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