The treatment of propene with $C l_{2}$ at $500 - 600^{0} C$ produces:

1,2-dichloro propane

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allyl chloride

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2,3-dichloro propene

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1,3-dichloro propene

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Solution

The correct option is B allyl chloride
When alkene reacts with $C i_{2}$ at $500 - 600^{0} C$ then it undergoes chlorination reaction to form allyl chloride as a product. This reaction is a substitution reaction.

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