The triangle ABC has a line AP and the Perpendicular AO.
If Ratio of BO and OC is 10 : 7 and Area of Triangle AOC = 42cm2 , Find the Area of full triangle ABC
102cm2
Area of Triangle AOC : Area of triangle AOB = OC : BO = 7 : 10
10(Area of Triangle AOC) = 7(Area of triangle AOB)
⇒ 7(Area of triangle AOB) = 10 × 42 = 420cm2
⇒ 60cm2 = 4207 = 60cm2
∴ Area of triangle ABC = Area of Triangle AOC + Area of triangle AOB = 42 + 60 = 102cm2