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Vertices of Plane Figures

The triangle ...

Question

The triangle formed by the normal to the curve $f (x) = x^{2} - a x + 2 a$ at the point $(2, 4)$ and the coordinate axes lies in second quadrant, if its area is $2$ sq units, then $a$ can be

2

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\frac{17}{4}

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5

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\frac{19}{4}

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Solution

The correct options are
B $\frac{17}{4}$
C $5$

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f (x) = x^{2} - a x + 2 a

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